What volume of a 0.152 M potassium hydroxide solution is required to neutralize 10.2 ml of a 0.198 M hydrochloric acid solution?

First write down the BALANCED reaction equ'n.

KOH + HCl = KCl + H2O

We note the molar ratiOS are all 1:1 :: 1:1

Next using the moles rq'n

moles = [conc] x vo;(mL) / 1000

mol(HCl) = 0.198 X 10.2 / 1000

mol(HCl) = 0.0020196 moles

By ratio equaivalence above

moles(KOH) = 0.0020196 moles

Using the same equation as above.

0.0020196 = 0.152 X vol(mL) / 1000

vol(mL) = 1000 x 0.0020196 / 0.152

vol(NaOH) = 13.2868 mL. The answer!!!!!