in those 10 balls we can have any combination...I am using here multinomial...
X=No. of red balls(0,1...10)
y=No. of green balls(0,1...10)
z=No. of white balls(0,1...10)
we need co-efficient of x^10 in (x^0+x^1+...+x^10)^3
that is (10+3-1)C3=12C3
Arrangement is also considered here
Copyright © 2026 eLLeNow.com All Rights Reserved.