Let's translate this math problem into 2 equations.
"One number is 4 more than 3 times another."
Let's call our first number A. Our second number will be B.
A = 3B + 4 (3 times the 2nd number, and then "4 more")
"The sum of the two numbers is 24."
A + B = 24.
Now we can use our 2 equations to find out exactly what each number is!
We'll use a method called substitution to help us.
We already know what A is, in terms of B. (A = 3B +4)
Substitute 3B +4, with parenthesis, wherever you see A in the 2nd equation.
A + B = 24
(3B + 4) + B = 24
Now simplify.
4B + 4 = 24
4B = 20
B = 5.
Our 2nd number, which we called B, is 5.
Use substitution again to find out what A is. Use the 1st equation, since it already tells us what A is, by using B.
A = 3B + 4
A = 3(5) + 4
A = 15 + 4
A = 19.
To check, substitute A = 19 and B = 5 into either equation, preferably both!
A = 3B + 4
19 = 3(5) + 4
19 = 15 + 4
19 = 19 (check)
A + B = 24
19 + 5 = 24
24 = 24 (check)
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