How many grams of Na2CO3 are conained in 0.400 L of 0.250 M Na2CO3?

To find the grams of Na2CO3 in 0.400 L of a 0.250 M solution, first calculate the moles of Na2CO3 using the formula: moles = molarity × volume. This gives you 0.250 moles/L × 0.400 L = 0.100 moles. The molar mass of Na2CO3 is approximately 106 g/mol, so multiply the moles by the molar mass: 0.100 moles × 106 g/mol = 10.6 grams. Thus, there are 10.6 grams of Na2CO3 in 0.400 L of a 0.250 M solution.