How much energy is required to break apart nucleus of 125.5 grams of aluminum-27?

To calculate the energy required to break apart the nucleus of aluminum-27, we first need to know the binding energy per nucleon. Aluminum-27 has a binding energy of about 7.5 MeV per nucleon. Given that aluminum-27 has 27 nucleons, the total binding energy is approximately 202.5 MeV. To convert this energy to joules, we use the conversion factor (1 \text{ MeV} \approx 1.6 \times 10^{-13} \text{ J}), resulting in about (3.24 \times 10^{-11} \text{ J}) for the entire nucleus.