When you throw lollipops into the air with a velocity of 3ms what is the maximum height?

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1080745

2026-05-07 01:45

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The maximum height of the lollipops can be calculated using the kinematic equation ( \text{max height} = \frac{v^2}{2g} ), where ( v = 3ms ) and ( g = 9.81ms^2 ) (acceleration due to gravity). Plugging in the values, we get ( \text{max height} = \frac{3^2}{2 \times 9.81} \approx 0.46m ).

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