What is the equilibrium constant expression for Fe3 (aq) SCN-(aq)FeSCN2 (aq) if the equilibrium constant is 78?

The equilibrium constant expression for the reaction involving iron(III) ions (Fe³⁺), thiocyanate ions (SCN⁻), and the complex ion iron(III) thiocyanate (FeSCN²⁺) can be written as:

[ K = \frac{[FeSCN^{2+}]}{[Fe^{3+}][SCN^{-}]} ]

Given that the equilibrium constant ( K ) is 78, this means that at equilibrium, the concentration of the complex ion FeSCN²⁺ is 78 times the product of the concentrations of Fe³⁺ and SCN⁻.