How many moles of anions are in 33.4 g of AlF3?

molar mass AlF3 = 83.98 g/mole33.4 g AlF3 x 1 mole/83.98 g = 0.398 moles

Each mole of AlF3 contains 3 moles of F- anions, because AlF3 ==> Al^3+ + 3F^-.

Thus, moles of anions = 3 x 0.398 = 1.19 moles of anions