Find three consecutive integers whose sum is 126?

Let the intgers be n- 1 n , & n+1 . This is consecutive.

Hence

Adding

(n-1) + n + ( n +1) = 126

Add the LHS

3n = 126

Divide both sides by '3'

n = 42

Hence n- 1 = 41

& n +1 = 43

So the consecutive integers are 41,42, & 43.