What is the approximate freezing point depression of 0.020m aqueous NaBr solution?

The freezing point depression (( \Delta T_f )) can be calculated using the formula ( \Delta T_f = i \cdot K_f \cdot m ), where ( i ) is the van 't Hoff factor, ( K_f ) is the freezing point depression constant for water (approximately 1.86 °C kg/mol), and ( m ) is the molality. For NaBr, which dissociates into two ions (Na(^+) and Br(^-)), ( i = 2 ). Therefore, for a 0.020 m solution of NaBr, the freezing point depression would be approximately ( \Delta T_f = 2 \cdot 1.86 \cdot 0.020 \approx 0.075 °C ).