What five consecutive numbers make 115?

Let the consecutive numbers be n,n+1, n+2, n+3, & n+ 4.

Add

n + (n+1)+(n+2) + (n + 3) + ( n + 4) = 115

5n + 10 = 115

5n = 105

n = 21

N+1 = 22

n+2 = 23

n+3 = 24

n + 4 = 25

So the five consecutive numbers are 21,22,23,24 & 25.