What happens to the perimeter of a square if the length of a side is doubled?

If the length of a side of a square is doubled, the perimeter also doubles. The perimeter of a square is calculated as ( P = 4 \times \text{side length} ). Therefore, if the original side length is ( s ), the new side length becomes ( 2s ), resulting in a new perimeter of ( P = 4 \times 2s = 8s ), which is twice the original perimeter.