At what distance from the Earth will a spacecraft traveling directly from the Earth to the Moon experience zero net force because the Earth and Moon pull with equal and opposite forces?

First of all, once you are in a spaceship, you won't feel gravitation, because you are in "free fall".

Anyway, to calculate this, consider that the Sun has 330,000 times the mass of Earth. Also consider the inverse-square relation. Therefore, for the two forces to cancel, the object would have to be square-root(330,000) or about 574 times farther from the Sun, than from the Earth - a distance of about 260,000 kilometers from Earth.

First of all, once you are in a spaceship, you won't feel gravitation, because you are in "free fall".

Anyway, to calculate this, consider that the Sun has 330,000 times the mass of Earth. Also consider the inverse-square relation. Therefore, for the two forces to cancel, the object would have to be square-root(330,000) or about 574 times farther from the Sun, than from the Earth - a distance of about 260,000 kilometers from Earth.

First of all, once you are in a spaceship, you won't feel gravitation, because you are in "free fall".

Anyway, to calculate this, consider that the Sun has 330,000 times the mass of Earth. Also consider the inverse-square relation. Therefore, for the two forces to cancel, the object would have to be square-root(330,000) or about 574 times farther from the Sun, than from the Earth - a distance of about 260,000 kilometers from Earth.

First of all, once you are in a spaceship, you won't feel gravitation, because you are in "free fall".

Anyway, to calculate this, consider that the Sun has 330,000 times the mass of Earth. Also consider the inverse-square relation. Therefore, for the two forces to cancel, the object would have to be square-root(330,000) or about 574 times farther from the Sun, than from the Earth - a distance of about 260,000 kilometers from Earth.