If a normally distributed group of test scores have a mean of 70 and a standard deviation of 12 find the percentage of scores that will fall below 50?

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Answer

1179048

2026-04-20 05:20

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X = 50 => Z = (50 - 70)/12 = -20/12 = -1.33

So prob(X < 50) = Prob(Z < -1.33...) = 0.091

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