What is the molarity of a solution prepared by dissolving 2.41 g of potassium iodide KI in 100 mL of water?

Find moles potassium iodide first.

2.41 grams KI (1 mole KI/166 grams) = 0.01452 moles KI

Molarity = moles of solute/Liters of solution ( 100 ml = 0.1 Liters )

Molarity = 0.01452 moles KI/0.1 Liters

= 0.145 M KI solution

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