Bill and Joe have 60 dollars between them. Bill has half as much as Joe. How much does Bill have?

Let Joe's amount be represented as ( J ) and Bill's amount as ( B ). According to the problem, ( B = \frac{1}{2}J ) and ( B + J = 60 ). Substituting the first equation into the second gives ( \frac{1}{2}J + J = 60 ), which simplifies to ( \frac{3}{2}J = 60 ). Solving for ( J ) gives ( J = 40 ), and substituting back, ( B = \frac{1}{2} \times 40 = 20 ). Therefore, Bill has 20 dollars.