How much work is done when a 6.0 n weigh is raised 2.0 meters off the ground?

Work is calculated using the formula ( W = F \times d \times \cos(\theta) ), where ( W ) is work, ( F ) is the force, ( d ) is the distance moved, and ( \theta ) is the angle between the force and the direction of motion. In this case, the force (weight) is 6.0 N, the distance is 2.0 m, and the angle ( \theta ) is 0 degrees (since the force and motion are in the same direction). Therefore, the work done is ( W = 6.0 , \text{N} \times 2.0 , \text{m} = 12.0 , \text{J} ).