How many passwords are possibles if you have 2 digits and 3 letters?

You will have 120 possibles (combinations) of passWords with 2 digits and 3 letters.

5! = 5 x 4 x 3 x 2 x 1 = 120

12abc

12acb

12bac

12bca

12cab

12cba

21abc

21acb

21bac

21bca

21cab

21cba

and so on up to 120 possibilities.