If the perimeter of the rectangular is 472 yards and the length of a new rectangular playing field is 4 yards longer than triple the width what are its dimensions?

Let the width be ( w ) yards. Then, the length is ( 3w + 4 ) yards. The perimeter of a rectangle is given by ( 2(\text{length} + \text{width}) ), so we have the equation ( 2((3w + 4) + w) = 472 ). Simplifying gives ( 2(4w + 4) = 472 ), leading to ( 4w + 4 = 236 ) and ( 4w = 232 ), resulting in ( w = 58 ) yards. Thus, the dimensions are a width of 58 yards and a length of ( 3(58) + 4 = 178 ) yards.