If 425 joules are absorbed from the higher temperature reservoir and 295 joules of that is passed onto the lower temperature reservoir how much work has been done by the system?

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1074038

2026-05-04 05:25

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The work done by the system can be calculated by finding the difference between the heat absorbed from the high-temperature reservoir and the heat passed onto the low-temperature reservoir. In this case, the work done by the system is 130 joules (425 joules - 295 joules).

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