To determine how many grams of aluminum hydroxide can be produced from 5.50 grams of aluminum sulfide (Al₂S₃), we first need to know the balanced chemical reaction involved. The reaction between aluminum sulfide and water produces aluminum hydroxide and hydrogen sulfide. The molar mass of Al₂S₃ is approximately 150.17 g/mol, and that of aluminum hydroxide (Al(OH)₃) is about 78.00 g/mol. Using stoichiometry, 1 mole of Al₂S₃ produces 2 moles of Al(OH)₃; thus, from 5.50 g of Al₂S₃, we can calculate that it can yield approximately 7.30 grams of aluminum hydroxide.
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