What will be the final temperature if 1600 cal of heat is given to an ice block of mass 20 grams?

I must assume that the ice block is at an initial temperature of 0o C. I also need to work in joules,. so I will convert the calories to joules.

1600 cal. (4.184 joule/1 cal.)

= 6694.4 joules

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6694.4 J = (20 grams H2O)(4.180 J/gC)(Tf - 0o C)

6694.4/83.6 = Tf

= 80o Celsius

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