What are the instruction of ias computer?

Instruction

Type

Opcode

Symbolic

Representation

Description

Data transfer

00001010

00001001

00100001

00000001

00000010

00000011

00000100

LOAD MQ

LOAD MQ,M(X)

STOR M(X)

LOAD M(X)

LOAD -M(X)

LOAD |M(X)|

LOAD -|M(X)|

Transfer contents of register MQ to the accumulator AC

Transfer contents of memory location X to MQ

Transfer contents of accumulator to memory location X

Transfer M(X) to the accumulator

Transfer -M(X) to the accumulator

Transfer absolute value of M(X) to the accumulator

Transfer -|M(X)| to the accumulator

Unconditional

branch

00001101

00001110

JUMP M(X,0:19)

JUMP M(X,20:39)

Take next instruction from left half of M(X)

Take next instruction from right half of M(X)

Conditional

branch

00001111

00010000

JUMP+M(X,0:19)

JUMP+M(X,20:39)

If number in the accumulator is nonnegative, take next instruction from left half of M(X)

If number in the accumulator is nonnegative , take next instruction from right half of M(X)

Arithmetic

00000101

00000111

00000110

00001000

00001011

00001100

00010100

00010101

ADD M(X)

ADD |M(X)|

SUB M(X)

SUB |M(X)|

MUL M(X)

DIV M(X)

LSH

RSH

Add M(X) to AC; put the result in AC

Add |M(X)| to AC; put the result in AC

Subtract M(X) from AC; put the result in AC

Subtract |M(X)} from AC; put the remainder in AC

Multiply M(X) by M(Q); put most significant bits of result in AC, put less significant bits in M(Q)

Divide AC by M(X); put the quotient in MQ and the remainder in AC

Multiply accumulator by 2 (i.e., shift left one bit position)

Divide accumulator by 2 (i.e., shift right one bit position)

Address modify

00010010

00010011

STOR M(X,8:19)

STOR M(X,28:39)

Replace left address field at M(X) by 12 right-most bits of AC

Replace right address field at M(X) by 12 right-most bits of AC