At what temperature would a reaction with H-220kjmol and S-0.05kj(molK) be spontaneous?

To determine the temperature at which the reaction becomes spontaneous, we use the Gibbs free energy equation: ΔG = ΔH - TΔS. A reaction is spontaneous when ΔG is less than zero. Given ΔH = -220 kJ/mol and ΔS = 0.05 kJ/(mol·K), we set ΔG to zero and solve for T: 0 = -220 kJ/mol - T(0.05 kJ/(mol·K)). Rearranging gives T = 2200 K, indicating that the reaction is spontaneous at temperatures above 2200 K.