What is the sum of the interior angles of a 102 sided-polygon?

Remember the two equations.

Exterior angle = 360 / no. of sides.

Interior angle = 180 - exterior angle.

So for 102 sided polygon.

exterior angle = 360/102 = 3.5294...

Interior angle = 180 - 3.5294... = 176.4706....

Hence sum of the 102 sided polygon's angles is

102 X 176.4706 = 18,000 degrees. ( to nearest degree).