What kind of nuclear reaction is seen in 14662Sm 14260Nd plus 42He?

The nuclear reaction involving (^{146}{62}\text{Sm}) (samarium-146) and (^{4}{2}\text{He}) (alpha particle) producing (^{142}_{60}\text{Nd}) (neodymium-142) is an example of an alpha decay or a nuclear fusion process where an alpha particle is absorbed. In this case, the samarium nucleus captures the alpha particle, resulting in the formation of neodymium and releasing energy. This type of reaction is typical in the context of nucleosynthesis in stars or certain radioactive decay processes.