How many atoms are in 177 g of calcium?

To find the number of atoms in 177 grams of calcium, first determine the number of moles of calcium using its molar mass, which is approximately 40.08 g/mol. Dividing 177 g by 40.08 g/mol gives about 4.41 moles of calcium. Since one mole contains approximately (6.022 \times 10^{23}) atoms (Avogadro's number), multiplying 4.41 moles by (6.022 \times 10^{23}) results in roughly (2.65 \times 10^{24}) atoms of calcium.