How many atoms are in 0.700g of P2O5?

To find the number of atoms in 0.700 g of P₂O₅, first calculate the molar mass of P₂O₅, which is approximately 142.0 g/mol (with phosphorus at about 31.0 g/mol and oxygen at about 16.0 g/mol). Next, determine the number of moles in 0.700 g by dividing by the molar mass: 0.700 g / 142.0 g/mol ≈ 0.00493 moles. Since each formula unit of P₂O₅ contains 7 atoms (2 phosphorus and 5 oxygen), multiply the moles by Avogadro's number (approximately (6.022 \times 10^{23}) atoms/mol) to find that there are roughly (1.48 \times 10^{21}) atoms in 0.700 g of P₂O₅.