Which shows the inequality correctly solved for x when x 0?

To correctly solve an inequality for ( x ) when ( x > 0 ), you need to isolate ( x ) on one side of the inequality. For example, if you have the inequality ( 2x + 3 < 11 ), you would first subtract 3 from both sides to get ( 2x < 8 ), and then divide by 2 to find ( x < 4 ). Since ( x ) is also constrained to be greater than 0, the solution can be expressed as ( 0 < x < 4 ).