To calculate the formula mass of magnesium nitrate, Mg(NO₃)₂, you need to sum the atomic masses of its constituent elements. Magnesium (Mg) has an Atomic Mass of about 24.31 g/mol, nitrogen (N) is approximately 14.01 g/mol, and oxygen (O) is about 16.00 g/mol. The formula contains one magnesium atom, two nitrogen atoms, and six oxygen atoms, leading to a total mass of roughly 24.31 + (2 × 14.01) + (6 × 16.00) = 148.31 g/mol. Thus, the formula mass of Mg(NO₃)₂ is approximately 148.31 g/mol.
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