What volume of a 6.67m nacl solution contains 3.12 mol nacl?

To find the volume of a 6.67 M NaCl solution that contains 3.12 moles of NaCl, use the formula:

[ \text{Volume (L)} = \frac{\text{moles of solute}}{\text{molarity}} ]

Substituting the values:

[ \text{Volume} = \frac{3.12 , \text{mol}}{6.67 , \text{M}} \approx 0.467 , \text{L} ]

Thus, the volume of the solution needed is approximately 0.467 liters, or 467 mL.