What is the molarity of a sodium hydroxide solution made by combining 2.0 L of 0.60 M NaOH with 495 mL of 3.0 M NaOH Assume the volumes of the two solutions to be additive.?

2.0 L x 0.60 mol/L = 1.2 moles NaOH
0.495 L x 3.0 mol/L = 1.485 moles NaOH
Total moles NaOH = 2.685 moles NaOH
Total volume = 2.0 L + 0.495 L = 2.495 L
Final concentration of NaOH = 2.685 moles/2.495 L = 1.076 M = 1.1 M (to 2 significant figures)