What is the distance between the points 2 1 and 14 6 on a coordinate plane?

For (2,1) & ( 14,6)

Use Pythagoras.

d^2 = (2 - 14)^2 + ( 1 - 6)^2

d^2 = (-12)^2 + (-5)^2

d^2 = 144 + 25

d^2 = 169

d = sqrt(169)

d = 13