A 60 gram bullet is fired from a gun with 3150 joule of kinetic energy what is its velocity?

To determine the velocity of the bullet, we can use the formula for kinetic energy: KE = 0.5 * m * v^2, where KE is the kinetic energy, m is the mass, and v is the velocity. Given that the kinetic energy is 3150 joules and the mass is 60 grams (which is 0.06 kg), we can rearrange the formula to solve for v. Plugging in the values, we get 3150 = 0.5 * 0.06 * v^2. Solving for v, we find that the velocity of the bullet is approximately 250 meters per second.