The perimeter of a rectangle is 110 cm more than twice the width find the demensions of the rectangle?

The perimeter of a rectangle is twice the width added to twice the length -> 2(W) + 2(L)

We are told that for this rectangle the perimeter = 2(W) + 110

So for this rectangle 2(L) = 110

Therefore L = 55

But this does not tell us enough to work out the width

..... if the width is 1 cm then the perimeter would be 2(1) + 110

and if the width is 300 cm then the perimeter would be 2(300) + 110

In each case the perimeter meets the requirement of being 110 cm more than twice the width.