In triangle ABC C is 62 degrees a is 10 and b is 15 find side c?

In this specific example one would use the Law of Cosines. The Law of Cosines is defined as:

* a2 = b2 + c2 - 2bc(cos(A)) In this case, we need to switch the formula to fit our sides:

* c2 = a2 + b2 - 2ab(cos(C)) Now, we just input are given numbers into the equation:

* c2 = (10)2 + (15)2 - 2(10)(15)cos(62o) Make sure your calculator is in degree mode when solving this equation.

* c2 = (100) + (225) - (300)cos(62o) * c2 = 325 - 140.84 * c2 = 184.16 (Square root each side)

* c = 13.57