The perimeter of a rectangle is 44 m. The base is eleven less than two times the base. What is the height?

Suppose base and height are b and h. 2b+2h=44 (the perimeter includes two bases and two widths) b=2b-11 base is 11 less than two times base Subtract b from both sides: 0=2b-11-b, b-11=0, b=11 2b=22 2b+2h=44, 22+2h=44, 2h=44-22=22, h=11 So the rectangle is a square with side 11.