What is the area of the rectangle whose sides are twice as long as the sides of a smaller rectangle whose area is 17cm2?

If the area of the smaller rectangle is 17 cm², then its length and width can be denoted as ( l ) and ( w ), where ( l \times w = 17 ) cm². The area of the larger rectangle, whose sides are twice as long, would be ( (2l) \times (2w) = 4(l \times w) ). Therefore, the area of the larger rectangle is ( 4 \times 17 = 68 ) cm².