In a certain algebra 2 class 27 students12 of them play basketball and 16 of them play baseball.there are 5 students who play both sports.What is the probability that a student chosen randomly from th?

To find the probability that a randomly chosen student from the class plays either Basketball or Baseball, we first calculate the number of students who play at least one of the sports using the principle of inclusion-exclusion. The number of students who play basketball or baseball is given by:

[ n(B \cup S) = n(B) + n(S) - n(B \cap S) = 12 + 16 - 5 = 23 ]

Thus, the probability that a randomly selected student plays either basketball or baseball is:

[ P(B \cup S) = \frac{n(B \cup S)}{n(T)} = \frac{23}{27} ]

Therefore, the probability is (\frac{23}{27}).