What is the equation and area of a circle whose diameter end points are at 2 -3 and 8 7 on the Cartesian plane showing work?

Diameter end points: (2, -3) and (8, 7)

Centre of circle: (5, 2)

Length of diameter: 2 Times Square root of 34

Equation: (x-5)^2+(y-2)^2 = 34 which in effect is the radius squared

Area in square units: 34*pi