What is the mass in grams of 9.30 1024 molecules of methanol CH3OH?

To find the mass of 9.30 × 10²⁴ molecules of methanol (CH₃OH), we first need to calculate the number of moles. Using Avogadro's number (6.022 × 10²³ molecules/mole), we find that 9.30 × 10²⁴ molecules corresponds to approximately 15.4 moles. The molar mass of methanol is about 32.04 g/mol, so the total mass is approximately 15.4 moles × 32.04 g/mol = 492.38 grams.