What is the equation of a line passing through (3 4) and having a slope of -5?

To find the equation of a line with a slope of -5 that passes through the point (3, 4), you can use the point-slope form of the equation, which is ( y - y_1 = m(x - x_1) ). Substituting the point (3, 4) and the slope (-5), the equation becomes ( y - 4 = -5(x - 3) ). Simplifying this gives ( y = -5x + 19 ). Thus, the equation of the line is ( y = -5x + 19 ).