What is the change in entropy when 25 kg of ice melts at 0 C?

To determine the change in entropy when 25 kg of ice melts at 0°C, we can use the formula for entropy change, ΔS = Q/T, where Q is the heat absorbed and T is the temperature in Kelvin. The heat absorbed during melting is given by Q = m * L_f, where m is the mass and L_f is the latent heat of fusion for ice (approximately 334,000 J/kg). Thus, Q = 25 kg * 334,000 J/kg = 8,350,000 J. Since the melting occurs at 0°C (273.15 K), the change in entropy is ΔS = 8,350,000 J / 273.15 K ≈ 30,570 J/K.