To find the zeros of the function ( f(x) = x\sqrt{2} + 4x + 8 ), we set the equation equal to zero: ( x\sqrt{2} + 4x + 8 = 0 ). This can be rewritten as ( x(\sqrt{2} + 4) + 8 = 0 ). Solving for ( x ), we get ( x(\sqrt{2} + 4) = -8 ), leading to ( x = \frac{-8}{\sqrt{2} + 4} ). Thus, the zeros of the function are ( x = \frac{-8}{\sqrt{2} + 4} ).
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