The perimeter of a rectangle is 32m and the area of the rectangle is 60 m2 Find the dimensions of the rectangle?

Perimeter, P = 32 m

Area, A = 60 m^2.

A = LW

60= LW

L = 60/W

P = 2L + 2W

32= 2L + 2W substitute 60/W for L;

32= 2(60/W) + 2W divide by 2 to both sides;

16 = 60/W + W multiply by W to both sides;

16W = 60 + W^2

0 = 60 + W^2 - 16W or,

W^2 - 16W + 60 = 0

W = [16 +,- square root of [16^2 - (4)(1)(60)]/2

W = [16 +,- square root of (256 -240)]/2

W = (16 +,- square root of 16)/2

W = (16 + 4)/2 or W = (16 - 4)/2

W = 20/2 or W = 12/2

W = 10 m or W = 6 m

L = 60/W = 60/10 or L = 60/6

L = 6 m or L = 10 m