What is the maximum number of grams of PH3 that can be formed when 6.20 g of phosphorous reacts with 6.oo g of hydrogen PH3?

To determine the maximum amount of PH3 that can be formed, we first find the limiting reactant by converting both reactants to moles and comparing the ratiOS. The balanced chemical equation is 4P + 6H2 -> 4PH3. From the calculations, we find that phosphorus is the limiting reactant. Therefore, all the phosphorus will be used up, and the maximum amount of PH3 that can be formed is 6.20 g.