What is the equivalent resistance if six 18 kOhm resistors are connected in 1. series 2. parallel as was asked by Mackey90 on 8 December 2008?

6 separate 18kOhm resistors wired in series make a total resistance of:

18k+18k+18k+18k+18k+18k which is 108 kOhm.

6 separate 18kOhm resistors wired in parallel make a total resistance of:

1/[(1/18k) + (1/18k) + (1/18k) + (1/18k) + (1/18k) + (1/18k)] which is 3 kOhm.