What is the equation of the line whose coordinates are at 2 3 and 11 13?

To find the equation of the line passing through the points (2, 3) and (11, 13), we first calculate the slope (m) using the formula ( m = \frac{y_2 - y_1}{x_2 - x_1} ). This gives us ( m = \frac{13 - 3}{11 - 2} = \frac{10}{9} ). Using the point-slope form ( y - y_1 = m(x - x_1) ) with the point (2, 3), the equation becomes ( y - 3 = \frac{10}{9}(x - 2) ). Simplifying this, the equation of the line is ( y = \frac{10}{9}x + \frac{7}{9} ).