What is the center and radius of the circle with equation (x plus 9)2 (y plus 5)2 64?

(x + 9)^2 + ( y + 5)^2 = 64 = 8^2

This is in the Pythagorean form of a^2 + b^2 = r^2

The displacement of 'x' is '-9' and the displacement of 'y' is '-5'

Hence the centre as ( x,y) is (-9, -5)

The radius is 'r at '8 units'.