What would the final freezing point of water be if 3 mol of sugar were added to 1 kg of water kf1.86 c molkg for water and I 1 for sugar?

The freezing point depression formula is ΔT = i * Kf * m, where i is the van't Hoff factor, Kf is the cryoscopic constant (1.86°C kg/mol for water), and m is the molality of the solution. The van't Hoff factor for sugar is 1, so the molality of the solution is 3 mol / 1 kg = 3 mol/kg. Therefore, ΔT = 1 * 1.86 * 3 = 5.58°C. The final freezing point of water would be 0°C - 5.58°C = -5.58°C.